# Operations Management Home Work Harvard Case Solution & Analysis

Question 1

What would be the bottleneck resource?

The bottleneck resource is identified below:

 BOTTLENECK IDENTIFICATION Average Truck Delivery 75 bbls Barrels of berries at peak harvest 19000 Number of trucks 253.3 Total Hours 12 Hours Trucks per hour 21.1 Minutes per truck arrival 2.8 Minutes Barrels per minute 26.4 26.4 barrels per minutes x 70% wet berry ratio 18.5 26.4 barrels per minutes x 30% dry berry ratio 7.9 Plant Capacity (wet berries ) 600BBS/hour= 10 bbls/min Plant Capacity (Dry berries) 1500bbs/hour= 25 Dry berries arrival 7.92 < 25 No Bottleneck Wet berries arrival 18.47 > 10 Bottleneck Total wet berries 13300 Wet berries plant capacity 600 bbls/hour Total time required in 1 day to complete 19000 barrels 22.17 hours

Question 2

What would be the plant’s process capacity?

The process capacity for the shown below:

 PLANT'S PROCESS CAPACITY RESOURCE POOL EFFECTIVE CAPACITY,BBLS/HR Dumping Capacity Kiwanee dumpers 5 Avg time to dump 7.5 minutes Avg weight in trucks 75 bbls Total dumping capacity 3000 Holding Capacity Total holding (1-16) 4000 Total Holding (17-24) 2000 Total Holding (25-27) 1200 DE stoning Capacity Total de-stoning capacity 4500 DE chaffing capacity Total de-chaffing capacity 4500 Separator Capacity No. of Separator units 3 Total separator capacity 1200 Bagging station capacity Maximum output each day 8000 bbls Total capacity 667 bbls/day Bulk bin loading capacity No. of loaders for bulk bin 4 Total capacity 800 bbls/day Bulk truck loading capacity No. of loaders of bulk trucks 2 Total capacity 2000 bbls/day TOTAL PLANT PROCESS CAPACITY 23867 bbls/day

Question 3

Assuming that 12,600 wet berries arrive per day (over a 12 hour day from 7am to 7pm) – does the time at which the plant finishes processing the last wet berry change? Why?

If we assume that the total wet berries arriving per day is reduced to 12600 from 13300 as previously calculated, then based upon the plant capacity of 600 bbls per hour, the time when the last wet berry is processed is changed and it is decreased as seen below.

 Total wet berries arriving per day (assumed) 12600 Wet berries plant capacity 600 Total time required in 1 day to complete 19000 barrels 21 hours

The reason for this is that the bottleneck has been reduced from the process to a certain extent. It is the bottleneck of the process, which is causing delay in the processing of the wet berries at peak time period. The management needs to take steps to remove this bottleneck from the process for instance, the holding bin at level 1 (17-24) should be converted into the wet berries and should not include the dry berries. Another recommendation for the management is to invest over the temporary storage and in this manner to reduce the truck wait time by 0-20 minutes. The mangement needs to improve the scheduling of the process so that the bottleneck is reduced and utilization is increased for the complete process.

Escort Service

Question 1

On average, what fraction of the time is the escort busy? That is, if a student calls, what is the likelihood that the escort is currently occupied with another student?

 Standard Deviation for Call Receiving 15 Minutes Standard Deviation for picking & dropping a student 15 Minutes Total Available Time 1440 Minutes Escort Busy Time 15 Minutes Maximum fraction of escort busy time of total time 2.08% Minimum fraction of escort busy time of total time 0.00% Average fraction of escort busy time of total time 1.04%

Question 2

How much time does it take, on average, from the moment a student calls for an escort to the moment the student arrives at her/his destination?

 Escort Busy Time 15 Minutes Average time to pick & drop a student 15 Minutes Standard deviation for picking & dropping a student 15 Minutes Maximum average time from student calling & arriving at his destination 45 Minutes Minimum average time from student calling & arriving at his destination 15 Minutes Average time from student calling & arriving at his destination 30 Minutes

Question 3

Suppose that the escort service purchases a scooter that the escort can use to pick-up and transport students. This reduces the average amount of time it takes for him to pick up and transport a student to 5 minutes, although the coefficient of variation of this time remains 1. Under this new system, how much time does it take, on average, from the moment a student calls for an escort to the moment the student arrives at her/his destination?

Operations Management Home Work Case Solution

 Escort Busy Time 5 Minutes Average time to pick & drop a student 5 Minutes Standard deviation for picking & dropping a student 5 Minutes Maximum average time from student calling & arriving at his destination 15 Minutes Minimum average time from student calling & arriving at his destination 0 Minutes Average time from student calling & arriving at his destination 15 Minutes

Operations in Workplace

Question 1

Briefly describe your current job or most recent job/position – what are your responsibilities and how would you describe your contribution in the ‘value added transformations’ within your organization..............

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