Exercise 2 Solution
Part a
The probability of the formation of a waiting line in a triage service is 0.18%.
| a) | Average Number of arrivals per hour |
12 |
patients |
| Exponential Distribution | Negative | ||
| Triage duration |
3 |
minutes | |
| Average number of arrivals per hour (Meu) |
12 |
Patients | |
| x |
3 |
minutes | |
| Probability |
0.18% |
||
Part b
The average number of the patients in the waiting line is 0.6.
| b) | Average number of patients in waiting line per minute |
0.6 |
Patients |
Part c
The probability for a patient to wait more than 10 minutes in a waiting line is 89.52%.
| c). | Probability of waiting more than 10 minutes |
89.52% |
|
Part d
After the installation of the software the triage time is reduce to 1 minute and based upon that the new probability for the formation of a waiting line is 0%, therefore, the patients would not have to wait in the line and complain so the new software is recommended for the health service unit.
Exercise 2 Solution Case Solution
| d) | Average number of arrivals per hour (Meu) |
12 |
Patients |
| x |
1 |
minute | |
| New Probability of waiting line formation |
0% |
...................
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