Electrical Engineering lab report Case Solution And Analysis, HBR Case Study Solution & Analysis of Harvard Case Studies

Electrical Engineering lab report Case Study Solution

Table 2.2: Core Loss Data.
f = 30 Hz		f = 40 Hz		f = 50 Hz		f = 60 Hz
E_s	W	E_s	W	E_s	W	E_s	W
Volts	Watts	Volts	Watts	Volts	Watts	Volts	Watts
21	2.2	28	3.2	35	3.9	42	7
31	4.7	42	6.1	52	8	63	15
42	7	55	10	69	15	83	23
52	10	69	15	86	20	104	29
63	15	83	23	104	29	125	39

Table 2.3: Data Sheet for Eddy-Current and Hysteresis Losses.
	f = 30 Hz		f = 40 Hz		f = 50 Hz		f = 60 Hz
B_m	P_e	P_h	P_e	P_h	P_e	P_h	P_e	P_h
B_m	Watts	Watts	Watts	Watts	Watts	Watts	Watts	Watts
0.4	1.30000	0.06	2.311111111	0.08	3.611111111	0.1	5.2	0.12
0.6	2.80000	0.09	4.977777778	0.12	7.777777778	0.15	11.2	0.18
0.8	4.50000	0.12	8	0.16	12.5	0.2	18	0.24
1	4.50000	0.15	8	0.2	12.5	0.25	18	0.3
1.2	4.50000	0.18	8	0.24	12.5	0.3	18	0.36

With the help of table 2.3 we have generated a graph 02, according to which, as the value of B_mincreases the value of P_eincreases for a certain period of time but after that, the value becomes stable.On the other hand the value of P_hincreases proportionally. As the value of frequency increases; the value of P_eand P_halso increases.

Conclusion

The conclusion of the above paragraphs is in the core of the transformer when the current is passed or if we apply the power to both the losseseddy current and hysteresis loss occur, and in the result, we face loss in terms of heat, which increases the machine temperature. We can reduce these losses by changing the material of the core.If we change the material then the transformer or machines take less power and produce more output effectively and efficiently........................

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